Question 259482

Given the following enthalpy change values for the reactions below:

A + B → 2C ; ΔrH = -39.2 kJ mol-1

C + 2D → E + F  ; ΔrH = -296.8 kJ mol-1

½ E + G → H ;  ΔrH = 474.9 kJ mol-1

Calculate ΔrH for the following reaction (in kJ mol-1) using Hess’s Law:

A + B + 4D + 4G → 4H + 2F