An ideal gas undergoes a mechanically reversible process (constant pressure, constant temperature and adiabatic process. The gas entering a T1=650K and P1=10bar decreases its temperature at constant pressure where V2=2.91×10-³m³
Then, it went to isothermal process to decrease its pressure. Finally, the gas returns to its initial state. Take Cp=7/2 and Cv==5/2 R.
Calculate the following:
a. T2,P3, V1 and V3
b. Q, W,ΔU and ΔH